Given the following data:
P=2nm
Q=5nm
D1=60nm
D2=90nm

An aircraft was over at A at 2110 and at 2132 a fix was obtained over B. The heading of 222 degrees magnetic and TAS of 180knots were held constant between 2110 and 2132. The actual wind and velocity was closes to

A. 348 degrees Magnetic/32kts
B. 078 degrees Magnetic/32kts
C. 168 degrees Magnetic/32kts
D. 278 degrees Magnetic/32kts

Kindly requesting your assistance for this question.

A better idea might be for you to post your solution, warts and all. Then we can critique what you have done. That is a far better way to learn stuff than just being spoon fed the answers ....

Remember, in the exam (or the aeroplane) it's just Captain Speaking (ie you) with no help available from anywhere else ....

Thanks for that John.

Yes absolutely.
So I was finding it a bit hard to try and navigate from the information given above using just Track Error of 7 degrees.

I went on to compare the closing angle to calculate Track to intercept which was 10 degrees.

Because the Track Error was 7 degrees I went on to assume it corresponds with the opposite angle of 7 degrees for the drift and use it.

Time was 22 minutes and Distance was 60nm so my ground speed was Headwind of 16kts, when I plotted this into the flight computer my closest 179degrees/30knots

In which was just 10 degrees from C.

I know I am missing out on something here.

First BIG mistake is that I see no picture of what is going on here. Always avoid trying to do this stuff in your head at the learning stage. When you have it all under control, fine, but not at this stage.

Can you post a scan of a sketch of the story ? Often a sketch will show you where you have gone wrong with very little thought required.

Hint:

When you look at your sketch, you might see something which suggests that you may have omitted an item of data in the original question ?