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RMI Example
sydpilot
Topic Author
sydpilot created the topic: RMI Example
Hi Bob,
Can you please explain the workings of the RMI example on page 5.23.
This is my working but I'm not sure if it is correct.
FPT = 080.
HDG is 070. RMI is 55. 15 deg deflection. So this is 15 deg left drift.
If there is 15 deg left drift, to maintain FPL of 080, I would have to fly 095.
Intercepet by 30 degress is 80+30 = 110.
Firstly, there will be no questions on the RMI in the exam, mainly because it is so simple to read that the examiners can't think of a question to ask.
An RMI is simply an ADF needle that floats over the face of the DG. Whatever indication the needle gives is the actual magnetic track to or from the station. If you read the point of the needle, that will be the magnetic track that will take you to the station. If you read the tail of the needle, you will get the magnetic track from the station.
There is no need to any mental gymnastics, the RMI indicates the track to/from the station directly.
Yes, 165 would do the trick. No, there are no questions in the CPL NAV exam on combining the 1-60 rule with the ADF or VOR. You can expect questions to be limited to determining the track to or from the station when you are given the heading and ADF reading. Or, determining the ADF reading when you know the track to or from the station and your present heading.
According to the 'HAT TRICK', Heading +/- ADF = TRACK. So in this case, 135 +/- something = 140 from. The ADF would read +5from. i.e. 185 relative. Your answer is correct.