Sir please just explain this to me how to calculate this..question.
Cruising level= 060
Gs= 120
Rod= 500fpm
You are required to reach 3000ft by 10nm from destination. What distance from destination should you commence decend?
t=3000ft÷500ftpm=6 minutes
D= S×T
120×6=720÷60=12 NM
12nm+10nm=22nm
My answer was 22nm
Please just check and help me out.
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If 3000' is an altitude, your working is correct.
If 3000' is a height AGL, you will need to account for the aerodrome elevation.
Looks okay, I got 23NM but I used E6B computer and rounded the distance 13NM for the distance covered during the descent.
You state cruising level 060. I think levels normally apply above the transition layer. So unless it was FL 600 in the question, but I don't think it was because that would have to come accompanied with a QNH to allow the same datum to be used for correct measuring of vertical distance required to climb or descend.
[color=blue][i][b]I got 23NM but I used E6B computer and rounded the distance 13NM for the distance covered during the descent.[/b][/i][/color]
Then you are using your computer incorrectly. Can you take a photo of your settings and post them so we can sort out whatever problems you might be having with its use, please ?
[color=blue][i][b]I think levels normally apply above the transition layer.[/b][/i][/color]
"level" is just a generic term. It would have been better had the question referred to A060 to make it clearer that the intention was to refer to an altitude rather than a flight level.
Engineering specialist in aircraft performance and weight control.
Silly me. I misread my E6B. Yes it's 12 and subsequently 22.
Thanks John. Picture included highlighting my silly error!
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Good one - always best if you can spot the problems yourself - sticks in the memory cells far more effectively.
Engineering specialist in aircraft performance and weight control.
