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Page 43 Exercise 9 IREX

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 Renz
(@rmn_24)
Active Member Customer
Joined: 1 year ago
Posts: 5
Topic starter  

Hey,

I’m a little confused on how to obtain the ADF indication once the FPT is intercepted? Particularly for Exercise 9 ie question 1, ADF at intercept -30F = 150R. Can someone explain to me how it works?

Cheers



   
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(@harryaat)
New Member Customer
Joined: 1 year ago
Posts: 2
 

Hi,

Your aircraft is currently HEADING 175ºM
The ADF is pointing at 190º, which is +10º off the tail of the aircraft (With the tail of the aircraft indicated as 180º on the ADF)
HEADING ± ADF = TRACK
175 + 10 = 185
Therefore the aircraft is currently TRACKING 185º

You want to intercept your new track of 200º with a 30º intercept, so your required HEADING will be 230º (200+30)

If you use your H±A=T rule to calculate the new ADF indication
HEADING ± ADF = TRACK
230 ± ? = 200

We know the answer is -30… but there is no -30 on the ADF.
It is in relation to the tail of the aircraft (Represented a 180 on the ADF)
Therefore 180 - 30 = 150



   
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